১.
z = $\frac{2-3i}{2+i}$ হলে Re(z) = ?
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$-\frac{8}{5}$
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$-\frac{1}{5}$
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$\frac{1}{5}$
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$\frac{8}{5}$
ব্যাখ্যা
$\begin{aligned} & z=\frac{(2-3 i)(2-i)}{(2+i)(2-i)}=\frac{4-2 i-6 i+3 i^2}{4-i^2}=\frac{1-8 i}{5}=\frac{1}{5}+\left(-\frac{8}{5}\right) i \\ & \operatorname{Re}(z)=\frac{1}{5}\end{aligned}$