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$\left ( 6A \right )_{16}$
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$\left (5B \right )_{16}$
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$\left ( 91\right )_{16}$
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$\left ( 90\right )_{16}$
$\begin{aligned}(5 \mathrm{~A})_{16} & =(?)_{10} \\ (5 \mathrm{~A})_{16} & =5 \times 16^1+10 \times 16^0 \\ & =5 \times 16+10 \times 1 \\ & =(90)_{10} \\ \therefore(90)_{10} & +(1)_{10}=(91)_{10} .\end{aligned}$
$(91)_{10}=(5B)_{16}$। 91÷16=5 ভাগশেষ11(B); 5÷16=0 ভাগশেষ5।
$\therefore(91)_{10}=(5 B)_{16}$
অর্থাৎ, (5A)16 এর পরের সংখাটি (5B)16