ময়মনসিংহ বোর্ড ২০২৩

(AB)16 = (?)2

(AB)16 = $\underset{A}{1010}$ $\underset{B}{1011}$ = 10101011

(AB)16 (10101011)2

(AB)16 = (?)8

(AB)16= $\underset{A}{1010}$ $\underset{B}{1011}$ = $\underset{2}{010}$ $\underset{5}{101}$ $\underset{3}{011}$ = 253

$\begin{aligned} & \therefore(\mathrm{AB})_{16}=(253)_8 \\ & (\mathrm{AB})_{16}=(?)_2 \\ & (\mathrm{AB})_{16}=\mathrm{A} \times 16^1+\mathrm{B} \times 16^0 \\ & =10 \times 16+11 \times 1=160+11=171 \\ & \therefore(\mathrm{AB})_{16}=(171)_{10}\end{aligned}$

অর্থাৎ সঠিক উত্তর (i), (ii)

(100)2 = (?)16

(100)2 = $\underset{4}{0100}$

$\begin{aligned} & \therefore(100)_2=(4)_{16} \\ & (1 \mathrm{~A})_{16}+(4)_{16}=(1 \mathrm{E})_{16}\end{aligned}$